for _ in range(int(input())):
n = int(input())
b, res = bin(n)[2:], float('inf')
n = len(b)
for i in range(n):
if b[i] == '1':
c = "1" * i + "0" + "1" * (n - i - 1)
res = min(res, int(c, 2))
print(res)
#include<iostream>
#include<map>
#include<set>
#include<iterator>
#include<algorithm>
#include<vector>
#include <unordered_set>
#include<cmath>
#include<iomanip>
#include<utility>
using namespace std;
int main() {
int g; cin >> g; while (g--) {
double n; cin >> n;
long long int a = log2(n);
cout <<fixed<<setprecision(0)<< pow(2, a) - 1 << endl;
}
}
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